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15x^2-45x-60=0
a = 15; b = -45; c = -60;
Δ = b2-4ac
Δ = -452-4·15·(-60)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-75}{2*15}=\frac{-30}{30} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+75}{2*15}=\frac{120}{30} =4 $
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